A box has 4 white and 6 black balls. Probability of drawing a white then black without replacement?

A box has 4 white and 6 black balls. Probability of drawing a white then black without replacement?

Approach: P(W) * P(B|W).

4/15. (4/10) * (6/9) = 24/90 = 4/15.

Follow-up: What is the probability of drawing two white balls?

Key concepts: without replacement.